请各位高手指点一下，在一个xml文件里父节点下存在同名的子节点如下面的例子里<Shop>下有两个<Table>子节点，<Table>节点下又有相同的子节点<TR>. 想把这个xml结构用XSLT变一下如下面的例子:
原xml文件:
<Shop>
<Table>
<TR>
<TH>ID</TH>
<TH>Last Name</TH>
<TH>First Name</TH>
<TH>Product</TH>
<TH>Price</TH>
</TR>
<TR>
<TD>1000</TD>
<TD>Chen</TD>
<TD>jin</TD>
<TD>CD1</TD>
<TD>1,00</TD>
</TR>
<TR>
<TD>1001</TD>
<TD>Zhang</TD>
<TD>San</TD>
<TD>CD2</TD>
<TD>1.50</TD>
</TR>
<TR>
<TD>1002</TD>
<TD>Li</TD>
<TD>Si</TD>
<TD>DVD1</TD>
<TD>10.00</TD>
</TR>
</Table>
<Table>
<TR>
<TH>PID</TH>
<TH>Product Name</TH>
<TH>Total</TH>
<TH>Price</TH>
</TR>
<TR>
<TD>5010</TD>
<TD>CD1</TD>
<TD>3000</TD>
<TD>1,00</TD>
</TR>
<TR>
<TD>6001</TD>
<TD>CD2</TD>
<TD>2500</TD>
<TD>1.50</TD>
</TR>
<TR>
<TD>10202</TD>
<TD>DVD1</TD>
<TD>500</TD>
<TD>10.00</TD>
</TR>
</Table>
</Shop>
转变后想得到的结构:
<Shop>
<table>
<thead>
<tr>
<td>ID</td>
<td>Last Name</td>
<td>First Name</td>
<td>Product</td>
<td>Price</td>
</tr>
</thead>
<tbody>
<tr>
<td>1000</td>
<td>Chen</td>
<td>jin</td>
<td>CD1</td>
<td>1.00</td>
</tr>
<tr>
<td>1001</td>
<td>Li</td>
<td>Si</td>
<td>CD2</td>
<td>1.50</td>
</tr>
<tr>
<td>1002</td>
<td>Zhang</td>
<td>San</td>
<td>DVD1</td>
<td>10.00</td>
</tr>
</tbody>
</table>
<table>
<thead>
<tr>
<td>PID</td>
<td>Product Name</td>
<td>Total</td>
<td>Price</td>
</tr>
</thead>
<tbody>
<tr>
<td>5010</td>
<td>CD1</td>
<td>3000</td>
<td>1,00</td>
</tr>
<tr>
<td>6001</td>
<td>CD2</td>
<td>2500</td>
<td>1.50</td>
</tr>
<tr>
<td>10202</td>
<td>DVD1</td>
<td>500</td>
<td>10.00</td>
</tr>
</tbody>
</Table>
</Shop>
我写了xsl文件:
<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method = "xml" omit-xml-declaration = "yes" indent = "yes"/>
<xsl:template match="/">
<xsl:apply-templates select="Shop/Table"/>
</xsl:template>
<xsl:template match="Table">
<table>
<thead>
<xsl:for-each select="//TR[position()=1]">
<tr>
<xsl:for-each select="//TR[position()=1]/TH">
<td>
<xsl:value-of select="text()"/>
</td>
</xsl:for-each>
</tr>
</xsl:for-each>
</thead>
<tbody>
<xsl:for-each select="//TR[position()>=2]">
<tr>
<xsl:for-each select="//TR[position()>=2]/*">
<td>
<xsl:value-of select="text()"/>
</td>
</xsl:for-each>
</tr>
</xsl:for-each>
</tbody>
</table>
</xsl:template>
</xsl:stylesheet>
结果:
<table>
<thead>
<tr>
<td>ID</td>
<td>Last Name</td>
<td>First Name</td>
<td>Product</td>
<td>Price</td>
<td>PID</td>
<td>Product Name</td>
<td>Total</td>
<td>Price</td>
</tr>
<tr>
<td>ID</td>
<td>Last Name</td>
<td>First Name</td>
<td>Product</td>
<td>Price</td>
<td>PID</td>
<td>Product Name</td>
<td>Total</td>
<td>Price</td>
</tr>
</thead>
<tbody>
<tr>
<td>1000</td>
<td>Chen</td>
<td>jin</td>
<td>CD1</td>
<td>1,00</td>
<td>1001</td>
<td>Zhang</td>
<td>San</td>
<td>CD2</td>
<td>1.50</td>
<td>1002</td>
<td>Li</td>
<td>Si</td>
<td>DVD1</td>
<td>10.00</td>
<td>5010</td>
<td>CD1</td>
<td>3000</td>
<td>1,00</td>
<td>6001</td>
<td>CD2</td>
<td>2500</td>
<td>1.50</td>
<td>10202</td>
<td>DVD1</td>
<td>500</td>
<td>10.00</td>
</tr>
接下来5个同样的<tr>...</tr>
<tr>
......
</tr>
<table>
怎样将两个<Table>分开写道新的结构里呢？谢谢各位的指点！
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2007/11/30 22:01:00
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[原创]用XSLT 转换 XML格式问题
